here is a naive but working way to do it in ruby : https://gist.github.com/84962... | Hacker News

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erwanb on March 1, 2011 | parent | context | favorite | on: How a 19-Year-Old Raised $5 Million to Revolutioni...

here is a naive but working way to do it in ruby : https://gist.github.com/849625

ntoshev on March 1, 2011 | [–]

Python:

max((s[start:end] for start in xrange(len(s)) for end in xrange(start, len(s)) if s[start:end]==s[start:end][::-1]), key=len)

iworkforthem on March 1, 2011 | [–]

Thank you. 0.upto(string.length - password_length) do |index| that's the line of logic I didn't it get correct.

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